Question

(x+8)(x-19)(x+1)>0

Answer 1

{x\[\left| 5 \right|\]

Answer 2

we know when that =0 :)

Answer 3

the solution is 0 then

Answer 4

wait does it mean no solution?

Answer 5

<......-8........-1.......19.......>

now we have to determine which intervals are greater than 0

Answer 6

lets pick some numbers to test out that are clearly within the intervals:

x=-10

(-10+8)(-10-19)(-10+1)>0

(-2)(-29)(-9)>0 ; and -.-.- = - so this is false

Answer 7

<......-8........-1.......19.......>
-

try x=0 is simple enough:

(0+8)(0-19)(0+1)>0

(8)(-19)(1) > 0 ; +.-.+ = - so this is false



<......-8........-1.......19.......>
- -

im gonna assume we can say it greater than 0, or +, on the other 2 intervals

Answer 8

but thats a bad assumption, since it COULD touch and turn ... we better check them to be sure

Answer 9

try x = -5

(-5+8)(-5-19)(-5+1)>0
+ - - = + its good



<......-8........-1.......19.......>
- + -


and x= 20

(20+8)(20-19)(20+1)>0
+ + + = + its good



<......-8........-1.......19.......>
- + - +

Answer 10

that wud be true?

Answer 11

so we can tell by our number chart ...

that it is greater than 0, or +, in the intervals: (-8,-1) U (19,inf)

Answer 12

never thought of it like that thanks!

Answer 13

your welcome, hope it helped ;)