find the obtuse angle between lines having the slopes 1/2 and -1/3
Using Law of Cosines, angle is 135 degrees From the slopes, draw a triangle connecting the 2 lines use Pythagorean theorem to hypothesize possible lengths of triangle
can you explain it to me?
|dw:1323012819886:dw| from the diagram, the angle between the horizontal and the line \(y=\frac{1}{2}x+c_2\) is \(a\), and the angle between the horizontal and the line \(y=-\frac{1}{3}x+c_1\) is \(b\).\[\tan(a)=\text{slope of line }y=\frac{1}{2}x+c_2\]so:\[\tan(a)=\frac{1}{2}\]similarly:\[\tan(b)=-\text{slope of line }y=-\frac{1}{3}x+c_1\]so:\[\tan(b)=\frac{1}{3}\] you can then use the tan rule for a+b to get:\[\tan(a+b)=\frac{\tan(a)+\tan(b)}{1-\tan(a)\tan(b)}=\frac{\frac{1}{2}+\frac{1}{3}}{1-\frac{1}{2}\cdot\frac{1}{3}}=\frac{\frac{5}{6}}{\frac{5}{6}}=1\]therefore:\[a+b=45^0\]therefore the obtuse angle between the two lines is:\[180^0-(a+b)=180^0-45^0=135^0\]
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