Question

how do you find xsinx = 0?

Answer 1

For that to be 0, either x = 0 or sinx = 0. I think you can do it from here?

Answer 2

x = 0

\[x = n \pi\]

where n can be all real numbers

Answer 3

oh wait, i was doing the problem wrong, so i actually need to find where f has a local maximum given f'(x) = xsinx - cosx

Answer 4

so you need then to find the zeros of the equation and see if they are local maximums or minimums

Answer 5

yeah, but what would be the first step to find the zeros?

Answer 6

i set it equal to zero right? and then what?

Answer 7

so set it equal to zero and find what x has to be for the whole equation to equal 0, there will be more than one answer most likely. then check a point slightly to the left of that and see if the derivative is positive or not.

Answer 8

alright, thanks!

Answer 9

no problem! good luck!

Answer 10

haha i'll need it

Answer 11

also check a point to the right and make sure it is negative, that way you know the 0 of the equation is a local max

Answer 12

okay! thanks