find all the other functions of θ if it is in the quadrant indicated . 1. SIN θ =4/5 (1ST QUADRANT) 2. COS θ = -12/13 (3RD QUADRANT) 3. COT θ = 4/3 (3RD QUAD) 4. SEC θ = -5/3 (3RD QUAD) 5. SIN θ = 7/25 (2ND QUAD)
You mostly have to use \[\sin^2(x) + \cos^2(x) = 1\] to find the missing one, as well as \[\tan(x) = \sin(x)/\cos(x)\]
so how do i know what's the answer i be looking on google but cant find any idea
I gave you the process with which you can find the missing one (simply replace sinx = 4/5 and solve for cos(x), for instance). You obviously have to know the definitions of each trig function too...
cosx=3/5
tanx=4/3
I will give you one example, but you must work out the rest yourself. sinx = 4/5, and we are in the first quadrant. Using \[\sin^2(x) + \cos^2(x) = 1 <=>(4/5)^2 + \cos^2(x) = 1 <=> \cos(x) = +/- \sqrt{1 -(4/5)^2}\] = +/- 3/5 Because we are in the first quadrant, the cosine is positive, so the solution is + 3/5
cos
yeah + or - 3/5
if it is in 1st quadrant it is positive right?
yeah but just in case if quad not given then u should write +or-
ok so hav u got it?
in the end i will use phytagorean theorem? then can i use calculator?
no need to use calc. please dont use it is very bad to use a calculator
The calculator is not needed for these, only the definitions of each trigonometric function, and the 2 identities which I gave you
Please read my posts carefully, it feels like you're skipping them.
yeah ringlum is right and his sols. are also right please read them
and btw if there are any Arsenal F.C fans please join my group 'Arsenal'
so if i feel no.1 and no.2 solution is the same?
because sin^2 (x) + cos ^2(x) = 1 right?
he just used the identities of his first post to write the sol. in his second post
yeah
waitin sis
(what I wrote applies to the first, number 1, you must do the same process or similar for each of the other ones)
-12/13 + sin^ (x) = 1 sin x =|dw:1323091704191:dw|
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