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Mathematics 18 Online
OpenStudy (anonymous):

I need a confirmation on this. http://openstudy.com/#/updates/4edd38aae4b01b4ec492d3d1

OpenStudy (anonymous):

I think you can do it a bit easier by just using the general formula: \[s(t)=s_0+v_0t+\frac{1}{2}at^2\], and just filling in the information given in the question.

OpenStudy (anonymous):

Hmm, never been introduced to that formula. o-o

OpenStudy (anonymous):

It might look more familiar in the form:\[s=ut+\frac{1}{2}at^2\]

OpenStudy (anonymous):

Emm, we ended up with s(t)= -cos(4t)+2t+6 ...

OpenStudy (anonymous):

The other method is correct as far as I can tell. Not sure what to tell you!

OpenStudy (anonymous):

What did you get with the other method?

OpenStudy (anonymous):

I think my formula may only work for constant acceleration now that I think about it. By 'the other method', I mean the one used by Mr. Math and yourself in http://openstudy.com/#/updates/4edd38aae4b01b4ec492d3d1

OpenStudy (anonymous):

Aaaah, okay. Either way, thanks. :]

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