I need a confirmation on this. http://openstudy.com/#/updates/4edd38aae4b01b4ec492d3d1
I think you can do it a bit easier by just using the general formula: \[s(t)=s_0+v_0t+\frac{1}{2}at^2\], and just filling in the information given in the question.
Hmm, never been introduced to that formula. o-o
It might look more familiar in the form:\[s=ut+\frac{1}{2}at^2\]
Emm, we ended up with s(t)= -cos(4t)+2t+6 ...
The other method is correct as far as I can tell. Not sure what to tell you!
What did you get with the other method?
I think my formula may only work for constant acceleration now that I think about it. By 'the other method', I mean the one used by Mr. Math and yourself in http://openstudy.com/#/updates/4edd38aae4b01b4ec492d3d1
Aaaah, okay. Either way, thanks. :]
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