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Mathematics 17 Online
OpenStudy (anonymous):

so if I have Y=e^(x-1)-1 find the range

OpenStudy (anonymous):

\[e^x>0\] so \[e^{x-1}-1>-1\]

OpenStudy (anonymous):

can the domain be -infinity to infinity

OpenStudy (anonymous):

From -0.4 to infinity according to the graph

OpenStudy (anonymous):

yes, you can raise e to any power

OpenStudy (anonymous):

can I put that in the calculsator and come up with the answer?

OpenStudy (anonymous):

You can come up to the answer using graphing calculator.

OpenStudy (anonymous):

I have that kind

OpenStudy (anonymous):

When you will see the graph then you can see the graph is going upwards from -0.4 towards infinity so range will be infinity.

OpenStudy (anonymous):

so the domain and range is the same Im confused

OpenStudy (anonymous):

For domain part you have to check all possible values of x, and when you will see the graph then you can see the graph is going from extreme left side towards extreme right side so domain will be from -infinity to +infinity.

OpenStudy (anonymous):

Always see horizontal line for domain part and vertical line for range part, because domain is all possible values of x and range is all possible values of y.

OpenStudy (anonymous):

ok so I had them back words that would make more sense to me now

OpenStudy (anonymous):

Yes!

OpenStudy (anonymous):

Do you have any doubt do far?

OpenStudy (anonymous):

*so

OpenStudy (anonymous):

no it makes more sense now

OpenStudy (anonymous):

Great!:)

OpenStudy (anonymous):

Thanks

OpenStudy (anonymous):

now if I have to find the y intercept of this same equation do I do it as follows

OpenStudy (anonymous):

For finding y-intercept we just plug 0 in place of x, or according to the graph just see, at which point graph is cutting the y-axis. because at y-axis the value of x is always equal to 0.

OpenStudy (anonymous):

So you can see at the point y=-0.4 the graph is cutting the y-axis, so y=-0.4 will be the answer for y-intercept.

OpenStudy (anonymous):

Is this clear so far Danyel?

OpenStudy (anonymous):

\[ y=e ^{(0-1)}-1\]

OpenStudy (anonymous):

ok yes it makes sense

OpenStudy (anonymous):

Okay! so it is equal to y=e^(-1)-1, or y=1/e-1.and value of 1/e is 0.3678

OpenStudy (anonymous):

So .3678-1 is equal to -0.63, but you will see the graph then you will see the exact value.

OpenStudy (anonymous):

And -0.63 and -0.4 are vary closer number, so if it is saying in the problem to find the answer using graph then we can say y-intercept as -0.4 and if use of graph is not allowed then answer will be -0.63

OpenStudy (anonymous):

Does this make sense to you?

OpenStudy (anonymous):

it says to graph the function then find all these and the asymptote as well

OpenStudy (anonymous):

so yes I use the graph right

OpenStudy (anonymous):

Okay! so we can use graphing calculator, because it is too lengthy to plot the graph of given exponential function, so our answer for y-intercept will be y=-0.4

OpenStudy (anonymous):

Yes! you are correct!

OpenStudy (anonymous):

yes this makes much better sense thank you

OpenStudy (anonymous):

You are most welcome!:)

OpenStudy (anonymous):

You have to find asymptote or you will do it by your own?

OpenStudy (anonymous):

I have to find it but I think it might be -1

OpenStudy (anonymous):

Can you recheck it again? It will be equal to 1

OpenStudy (anonymous):

By the way we have three rules also for finding horizontal asymptote.

OpenStudy (anonymous):

If the degree (the largest exponent) of the denominator is bigger than the degree of the numerator, the horizontal asymptote is the x-axis (y = 0).

OpenStudy (anonymous):

If the degree of the numerator is bigger than the denominator, there is no horizontal asymptote.

OpenStudy (anonymous):

what are those I haven't heard them

OpenStudy (anonymous):

If the degrees of the numerator and denominator are the same, the horizontal asymptote equals the leading coefficient (the coefficient of the largest exponent) of the numerator divided by the leading coefficient of the denominator).

OpenStudy (anonymous):

These are three rules for finding horizontal asymptote and for vertical asymptote we simply equate denominator with 0.

OpenStudy (anonymous):

Did you get these points?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

so does that mean we have o asympyote then herewith this one

OpenStudy (anonymous):

These all rule will not apply for this problem, these rules will apply when we have given fractional equation. we will get the horizontal asymptote from the graph in this problem.

OpenStudy (anonymous):

ok that is what I thought but had to check. \

OpenStudy (anonymous):

so when I look at the graph It looks like -1

OpenStudy (anonymous):

For horizontal asymptote we will see at which point the graph is cutting the horizontal line, Isn't it going through the point x=1 at the x-axis?

OpenStudy (anonymous):

yes i was thinking the y axis

OpenStudy (anonymous):

Not really! Here answer will be 1.

OpenStudy (anonymous):

Do you have any question so far?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

thank you sooooo much

OpenStudy (anonymous):

You are most welcome!:) Have a nice time ahead! Take care! Bye!

OpenStudy (anonymous):

bye

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