y=e^(-x)-e trying to find the range.
Waht's the range of \( e^x \) ?
What's
not sure
I think 1
or 0
Ah ... go back to your class notes or text book and figure it out. Otherwise you'll never be able to answer this question. No, {1} is not the range of e^x, nor {0}
Once you know that range of e^x, find the range of e^(-x); then the range of e^(-x)-e
You should definitely learn what the graph of y = e^x looks like. It's a very important function.
e\[ e ^{1}=e\]
Also you should know that e is a positive number and a positive number raised to ANY power is positive. So the range of y = e^x is the real numbers greater than 0
so where this is raise to a neg x does that mean it is all neg. numbers
\[ y^{-1} = 1/y \]
Hence if the range of e^x is all positive numbers, the range of e^(-x) is the reciprocal of all positive numbers, which is .....
NO!!!!!!!!! A positive number raised to ANY POWER AT ALL-POSITIVE, NEGATIVE, OR 0 IS POSITIVE!!!!!!!
You really should look up the graphs of these functions. So important.
i did i need to understand how to find it after looking at the graph
Please be patient I am just learning this sorry
So is the problem that you aren't quite sure what is meant by the term "range"?
yes
So I am going to draw you a picture and see if we can clarify.
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