Question

limits

Answer 1

\[\lim x->9 (x-9)\div (\sqrt{x}-3)\]

Answer 2

first make sure that you get
\[\frac{0}{0}\], which you do. then rationalize the denominator by writing
\[(\frac{x-9}{\sqrt{x}-3})\times (\frac{\sqrt{x}+3}{\sqrt{x}+3})\]
the denominator will be
\[x-9\] and you will then cancel, and replace x by 9 to get your limit