sec2x-secx+tan2x just simply
\[\sec^2x-\sec x+\tan^2x\]right?
ya
i got sec+1 and sec-1
I see 2tan^2x-secx+1 off the bat... can it be further simplified? hmm...
how did you get two answers? \[\sec x+1\] and \[\sec x -1\]?
doesn't seem to get much simpler: http://www.wolframalpha.com/input/?i=simplify+sec%5E2x-sec%28x%29%2Btan%5E2x
sec2-secx+sec2x-1
new problem?
2sec2-secx-1
npoe
old prob
so you typed it wrong, or is this what you are getting as an answer?
the solution u asked me how i got sec+1 and sec-1
tan2x can be sec2-1 all sec are there so we can sec+1 and sec-1
new problem is sec3x-secx=0
here's what I see...\[\sec^3x-\sec x=0\]\[\sec x(\sec^2x)-\sec x=0\]\[\sec x(\sec^2x-1)=0\]\[\sec x \tan^2x=0\]\[{\sin^2x \over \cos^3x}=0\to \sin x=0\]\[x=\left\{ n \pi: n=0,1,2... \right\}\]make sense?
no u should not use any identites in this u should same way like this x3-16x=0 just simply
but it is sec^3x-secx=0 equals signs usually mean solve, not simplify...
even so, all you want then is \[\sec^3x-\sec x=0\]\[\sec x(\sec^2x-1)=0\]\[\sec x(\sec x-1)(\sec x+1)=0\]that's as far as you can simplify without identities... Is that really what you are looking for? strange to have an algebra problem in trig like this o-0
we are practicing forctring before we go for originall one 2sin2+3sinx+1=0 this is reall onw
real what? sorry?
and PLEASE use the equation feature, sin2 means \[2\sin2\]I assume you mean\[2\sin^2x\]which is very different.
\[2\sin^2x+3sinx+1=0\]
thanks... so are we solving or just factoring?
now we are finding allsolutions from0,2pie
well first factor the form \[2x^2+3x+1=0\]then replace x with sin x and you should have your answer...
2x+1 and x+1
sin+1/2 ans sin=1
wow i got u thnx
hey is calculus bc is highest course
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