Use a table to find a z-score that fits the given conditions. Interpolate if necessary. 48% of the area under the standard normal curve is above the score.
Just use your normal distribution table. Find the z value that corresponds to 0.48 of the area ABOVE the score, so your z value will be positive because the 'score' is right in the middle where z=0. Having this positive z value means you have to take the percentage 1-0.48=0.52. The corresponding z value is 0.05. Check out khanacademy.org, there are some really useful tutorials on pretty much everything there.
okay so i guess i was doing it right! i got .05 as well. im confused on how to do this one though -- Determine the percent of data greater than z = -1.60 in a normal distribution. Round your answer to the nearest hundredth. Use a standard normal table if necessary.
you'll get a smaller value...maybe in the 0.1 range? for a percent. To get all the values greater, you'll have to go 1-(the value you got)
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