Question

how to order of operation with fractions six steps

Answer 1

can you rephrase the question?

Answer 2

how to solve problem number 1

Answer 3

alright this is gonna take a while to type so hold on one sec

Answer 4

So here's the initial problem:
\[(-9-(-1)) \div (-3/2) \div [(-1)^{(-11)\times(-3)}+(1/2)]\]
You need to do anything in parenthesis first so do (-11)*(-3) in the exponent first:
\[(-8) \div (-3/2) \div [(-1)^{33}+(1/2)]\]
Now you need to do the exponents next so calculate (-1)^33:
\[(-8) \div (-3/2) \div [-1+(1/2)]\]
Now we go back to doing what's in parenthesis so do -1+(1/2):
\[(-8) \div (-3/2) \div (-1/2)\]
Now we can divide, but dividing a fraction is the same as multiplying its inverse, so we get:
\[(-8) \times (-2/3) \times (-2)\]
Then just multiply -8 * (-2/3) and multiply that number by -2 and you get your answer:
\[(16/3) \times (-2) = (-32/3)\]
Final answer: (-32/3)

Answer 5

you got all that?

Answer 6

yep

Answer 7

thanks muchas gracias