Question

PLZ HELP ME :'(
See attachment for Q

Answer 1

\[t=\frac{d}{r} \]Solve the following for r, the speed for the first leg of the trip.\[\frac{94}{r}+\frac{22}{r-5}=2\]\[r=\frac{1}{2} \left(63+\sqrt{3029}\right)=59.02\text{ mph}, r-5=54.02\text{ mph} \]

Answer 2

it's saying 54.02 is wrong

Answer 3

Would you please post what it's saying the correct answer is? Then we can go from there.

Answer 4

i havent gottin the answer yet

Answer 5

Let's verify the solution. The following is a symbolic list of two fractions representing the times for the the first 94 miles and the second 22 miles respectively. The total distance is 116 miles. Replace r with the solution speed, 59.02, and evaluate the fractions with a calculator.\[\left\{\frac{94}{r},\frac{22}{r-5}\right\}\text{=}\left\{\frac{94}{59.02},\frac{22}{59.02-5}\right\}\text{=}\{1.59268,0.407257\}\]The sum of the calculated times should total 2 hours.\[1.59268+0.407257 = 1.99994 \text{ hours}, 2 \text{ for} \text{ our} \text{ purposes}.\]rate * time = distance. Multiply 59.02 times the first leg's time and add the result to 54.02 times the second leg's time.\[1.59268*59.02 +0.407257*54.02 = 116. \ \text{ miles}\]

Answer 6

i put 116 and it said this

Answer 7

\[\left\{\frac{94}{r}+\frac{22}{r-5}=2,\frac{22}{2-t}=\frac{94}{t}-5\right\}\]The above list of two equations represent two different ways to solve the problem. The first one solves for r, the first leg's speed, and the second equation solves for t, the first leg's time. Both approaches come to the same conclusion. You can work out the math.

The first one solves for rate or speed directly and that is what the problem narrative requested as an answer. Once the speed r is calculated, one simply subtracts 5 and the result is the other speed. The other solution requires that the solution for t be plugged into a convenient expression, that was used for the t solution, and then solve for the speeds.

Either solution approach does the job.