Question

secx cscx=tanx+cotx prove lhs=rhs

Answer 1

we've done this already ksaimouli!

Answer 2

ohh \[sinx/cscx+cosx/secx=sinxcscx\]

Answer 3

lhs = sinx / 1/sinx + cos x / 1 /cos x = sin^2x + cos^2x = 1 = sinx / sin x = sinxcscx

Answer 4

\[secx cscx\]\[=\frac{1}{cosx} \times \frac{1}{sinx}\]\[=\frac{1}{cosxsinx}\]we know that\[\sin^2x+\cos^2x=1\]so subsitute that instead of one\[\frac{\sin^2x+\cos^2x}{cosxsinx}\]\[=\frac{\sin^2x}{cosxsinx} + \frac{\cos^2x}{cosxsinx}\]\[=\frac{sinx}{cosx}+\frac{cosx}{sinx}= tanx+ cotx\]

Answer 5

= rhs