I need to find the derivative of y=3x(x^3/2). I know the answer is 2x(3x^2). I just dont know how to get it. help please
first multiply 3x and x^(3/2)
My teacher said that you need to use the product rule. which is the first times the deriviative of the second, plus the second times the derivative of the first.
Yup that is correct
derivative of 3x=3
Sorry the part isnt raised to 3/2 its x^3 divided by 2
and X^(3/2)= (3/2)x^(1/2)
YOu forgot to subtract one from the power
im sorry, rld is right, i got distracted
ya with the chat conversation!! :D
lol :( sorry
do u still need help with this, do u want me to do it again? no distractions:D
3*(x^(2/3))+(2/3)x^(1/2)*3x 3x^(2/3)+2^(3/2)
oh whoops io made a mistake
please. i know how to do0 it i just think im making a simple mistake
3x^(2/3)+2x(x^(1/2))
wait give me a sec
did u see where i said it wasnt raised to 2/3?
oh i see i was trying to see how u got that!!!
ok let me start from the begginning again
\[3x(x^{\frac{3}{2}})\]\[\frac{d}{dx}(3x(x^{\frac{3}{2}})=3x^{\frac{3}{2}}+3x(x^\frac{1}{2}) \times \frac{3}{2}\]
haha i didnt realize it until afterwards
I think the equation is different that is what maclovin is claiming
that it is 3x((x^3)/2)
\[=3x^{\frac{3}{2}} +\frac{9}{2}x^{\frac{3}{2}}\]
oh
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