Question

Linear Algebra Question:

Find a basis for nullspace(A)

A = | 2 6 -3 1 |
|-2 -3 2 0 |
|-2 -3 2 0 |
| 0 3 -1 1 |

The answer I get is [ 1 3 (-3/2) (1/2) ] , [ 0 1 (-1/3) (1/3) ] and it is wrong. What do you guys get?

Answer 1

\[\left[\begin{matrix}1/2\\-1/3\\0 \\ 1\end{matrix}\right],\left[\begin{matrix}1/2\\1/3\\1 \\ 0\end{matrix}\right]\]

Answer 2

how? :P

Answer 3

nevermind; i figured it out :D thanks