Linear Algebra Question:

Find a basis for nullspace(A)

A = | 2 6 -3 1 |
|-2 -3 2 0 |
|-2 -3 2 0 |
| 0 3 -1 1 |

The answer I get is [ 1 3 (-3/2) (1/2) ] , [ 0 1 (-1/3) (1/3) ] and it is wrong. What do you guys get?

Question

Linear Algebra Question:

Find a basis for nullspace(A)

A = | 2  6  -3  1 |
       |-2 -3  2  0 |
       |-2 -3  2  0 |
       | 0   3  -1 1 |

The answer I get is [ 1 3 (-3/2) (1/2) ] , [ 0 1 (-1/3) (1/3) ] and it is wrong. What do you guys get?

zarkon · Answer

$$\left[\begin{matrix}1/2\-1/3\0 \ 1\end{matrix}\right],\left[\begin{matrix}1/2\1/3\1 \ 0\end{matrix}\right]$$

anonymous · Answer

how? :P

anonymous · Answer

nevermind; i figured it out :D thanks