Question

HOw many solutions does this equation have?
(9/x-5)+(4/x^2-3x-10)=(6/x+2)

Answer 1

Put the denominator of each fraction it is own set of parenthesis, please.

In other words, please write
1 / (x+1)

instead of
1 / x + 1

:)

Answer 2

HOw many solutions does this equation have?
9/(x-5)+4/(x^2-3x-10)=6/(x+2)

Answer 3

Ok , that is much better. :) Thank you.

First question -- can you factor (x^2 - 3x -10) ?

Answer 4

yeah (x-3)(x+5) right?

Answer 5

wait nevermind

Answer 6

(x-5)(x+2)

Answer 7

Now what do I do

Answer 8

Now we find common denominators.

Answer 9

9/(x-5)+4/(x^2-3x-10)=6/(x+2) factor the quadratic to find

9/(x-5)+4/(x-5)(x+2)=6/(x+2) now make sure everything has a (x+2)(x-5) in the denominator.

Answer 10

Okay got that.

Answer 11

so do I times both sides by (x-5)(x+2)

Answer 12

then I get 9(x+2)+4=6(x-5) right?

Answer 13

then I get 9x=6x-52 then how do i solve that

Answer 14

?

Answer 15

>then I get 9(x+2)+4=6(x-5) right?

This is correct.

Now distribute the 9 and the 6.

Answer 16

yes so I get, 9x=6x-52