find the center of mass of a thin plate of a constant density d, covering the region bounded by the parabola y=5x^2 and the line y=20
centre of mass will certainly lie on the y axis by symmetry we can say that, now to find its y coordinate, Ycm=integral(y.dm )/integral dm calculating the numerator, consider thin strip of width dy at a distance y on the parabola dm= density * area =D*x*dy now x=(y/5)^1/2 integral (y.dm) = integ{y*(y/5)^1/2*D*dy } D(1/5)^1/2integ{y^3/2.dy } D(1/5)^1/2*{ y^5/2}*2/5 now calculating integ dm ={D*x*dy} =D(1/5)^1/2integ{y^1/2.dy} =D(1/5)^1/2* y^3/2 *2/3 now dividing integral (y.dm) and integ dm we get 3/5y (good question)
did u understand the solution?
still digesting the info...i'm working on my calc 2 final and for whatever reason totally blanked out and am suffering from a brain fart so i'm cramming to get it done in an hour :(
LOL, hmm thats pretty brave, best of luck
thank you
that previous question about finding volume that is some question, very good question, its ppl like you who make OS worth visiting
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