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Mathematics 18 Online
OpenStudy (anonymous):

for research purposes, a tornado can often be modeled as a right circular cylinder that rotates about its axis. A cylindrically shaped tornado has a core diameter of 200 feet. if the tornado has a maximum wind speed of 300 feet per second at the outer edge of the core, approximate the number of revolutions the core makes each minute. approximate to the nearest unit.

OpenStudy (anonymous):

the answer is 29 i'm just not sure how to solve it.

OpenStudy (anonymous):

also the equations could be v=s/t or v=rw but im not sure :/

OpenStudy (anonymous):

I'd go with \(v=r\omega\). What's the radius? Well it's half the diameter. What's the velocity? It's 300 ft/s. What's the angular velocity? That's what you have to find out! Your answer will come in the form of RADIANS per SECOND. Your answer needs to be in the form of REVOLUTIONS per MINUTE. How would you go about converting them? \[\]

OpenStudy (anonymous):

Hmm |dw:1323685680268:dw| Hmm The radius varies so is the wind speed constant at the outer edge or the wind speed mentioned in the question is for the largest radius

OpenStudy (anonymous):

@Ishaan "a tornado can often be modeled as a right circular cylinder" in the question :P

OpenStudy (anonymous):

Oh I read that as cone lol sorry hehe

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