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Find the limit(if it exists) As lim as x goes to 10 of 10-x/x^2-100
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\[\lim_{x \rightarrow 10}\frac{-(x-10)}{(x-10)(x+10)}\]
\[\lim_{x \rightarrow 10} \frac{-1}{x+10}\]
so the answer is -1/20? or infinity?
the function -1/(x+10) is continuous at x=10, so you can just substitute. Where would infinity come from now?
x goes to -10 would be a different story
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Okay Thank You guys. Not sure why I said infinity
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