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Mathematics 17 Online
OpenStudy (diyadiya):

Vector Algebra

OpenStudy (diyadiya):

Write the direction ratio's of the vector a=i + j - 2k and hence calculate its direction cosines i know the answer ,just want to know how to do it

OpenStudy (anonymous):

Do you know what is direction ratios and direction cosines ?

OpenStudy (diyadiya):

li'l bit

OpenStudy (anonymous):

Okay direction of vector is just the direction of the unit vector along A and it is given by $$ dir A = \frac {\vec{A}}{ | \vec{A}|} $$

OpenStudy (anonymous):

$$ \text{ Note: } \vec{A} \text{ cannot be null vector } $$

OpenStudy (anonymous):

The direction of a space vector in engineering practice often given by it's direction cosines.

OpenStudy (anonymous):

So if $$ \vec{A} = ba \vec{i} + b \vec{j} + c \vec{k} $$ be a space vector represented as an origin vector , and let $$\alpha$$, $$\beta $$ and $$\gama$$ be the angles that it makes with i,j,k. then $$ dir A = \cos \alpha \vec{i} + \cos \beta \vec{j} + \cos \gamma \vec{k}$$ The three coefficients are called the direction cosines of $$\vec{A}$$

OpenStudy (anonymous):

can you solve it now ?

OpenStudy (diyadiya):

okayy

OpenStudy (anonymous):

not okay .. tell me D :)

OpenStudy (diyadiya):

so What is direction ratios ?

OpenStudy (diyadiya):

??

OpenStudy (anonymous):

I suggest you take a look at this http://www3.ul.ie/~mlc/support/Loughborough%20website/chap9/9_3.pdf

OpenStudy (diyadiya):

ok so here a=1 ,b=1 and c=-2

OpenStudy (anonymous):

@Tomas.A: Typo .. OS should introduce typo

OpenStudy (anonymous):

@Diyadiya: Yes :D you are brilliant :D

OpenStudy (anonymous):

Hey lallalllalla :D

OpenStudy (lalaly):

Fooooooool:D:D:D

OpenStudy (diyadiya):

ok 1 min :D brb

OpenStudy (diyadiya):

So

OpenStudy (lalaly):

so?

OpenStudy (diyadiya):

is the ratio 1:1:-2 ?

OpenStudy (diyadiya):

?

OpenStudy (diyadiya):

Thanks FoolFM :)

OpenStudy (anonymous):

Yes it is .. sorry I went to dinner :(

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