Question

Solve 6x ≡ 9 (mod 21).

Answer 1

6x/21 = nR9

right?

Answer 2

ok

Answer 3

reduce it all by a factor of 3 maybe ...

2x/7 = n R3 ?? i dont do mods enough to be confident in them

Answer 4

9
9 +21 = 30 <- heres one
30+21 = 51
51+21 = 72 <- heres one
72+21 = 93
93+21 = 114 <- heres one

seems to be a pattern

Answer 5

6(5,12,19,...)

Answer 6

right what amistre said. you can write
\[6x\equiv 9(21)\]
\[6x\equiv 30(21)\]
\[x\equiv 5(21)\]

Answer 7

6(5+7n) ; n>=0 maybe

Answer 8

\[6x=9+21k\]
I like to enter in values of k to see what makes x an integer
k=0 => x not integer
k=1 => x=5
k=2 => x not integer
k=3 => x=12
k=4 => x not integer
k=5 => x=19
k=6 => x not intger
k=7 => x=26
so there is a pattern
x=5+7i for any integer i

Answer 9

oh did i screw up? maybe
\[6x\equiv 9(21)\]
\[2x\equiv 3(7)\]
\[2x\equiv 10(7)\]
\[x\equiv 5(7)\] is a better answer

Answer 10

i saw that but wasnt gonna say nuthin ;)

Answer 11

lol
back to the dungeon for me