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OpenStudy (zarkon):
F is a function of x
OpenStudy (anonymous):
well i do not know how to integrate e^(−3t)^4
OpenStudy (zarkon):
you don't need to
OpenStudy (zarkon):
just for clarification is it
\[\int\limits_{0}^{x}e^{(3t)^4}dt\]
or
\[\int\limits_{0}^{x}\left(e^{3t}\right)^4dt\]
OpenStudy (anonymous):
the first one
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OpenStudy (zarkon):
ok..I'll get you started...
\[F(0)=\int\limits_{0}^{0}e^{(3t)^4}dt=0\]
\[\frac{d}{dx}F(x)=\frac{d}{dx}\int\limits_{0}^{x}e^{(3t)^4}dt=e^{(3x)^4}\]
\[F'(0)=1\]
OpenStudy (anonymous):
972e^(81x^4) (x^2+108x^6)
OpenStudy (anonymous):
is that the second derivative ?
OpenStudy (anonymous):
?
OpenStudy (zarkon):
\[324x^3e^{81x^4}\]
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OpenStudy (anonymous):
do you mind explaining that, because i double checked with wolf ram alpha and i got my answer
OpenStudy (anonymous):
actually your answer is the first derivative. Isnt it ?
OpenStudy (anonymous):
?
OpenStudy (anonymous):
so is my answer 1944e^(81x^4)(1+(2754x^4)+(314928x^8)+5668704x^12)
OpenStudy (anonymous):
or f(0) of that which is 1944
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OpenStudy (anonymous):
because according to my program, none of those answers are right
OpenStudy (anonymous):
?
OpenStudy (zarkon):
972e^(81x^4) (x^2+108x^6) is the 3rd derivative not the 2nd