Question

Hey i have a question about dividing radicals(square roots) I'm going to write the equation in the comments!

Answer 1

\[5/(-5-3\sqrt{3})\]
please show work if you can!

Answer 2

I would try this:
5 / (-5-3*sqrt(3)) = -5 / (5+3*sqrt(3)) = -5 / (5+sqrt(27)) =
(now a trick when we multiply it all by 1)
= -5 / (5+sqrt(27)) * (5 - sqrt(27)) / (5 - sqrt(27)) =
= (-5) * (5 - sqrt(27)) / (25 - 27) =
5 * (5 - sqrt(27)) / 2

Is that what you want?
Hope it's clear how I did it..

Answer 3

i just dont get how -5*5 is equal to -5.. shouldnt it be -25?

Answer 4

And where exactly? Sorry, I can't see where I did 5*5..

Answer 5

(-5) * (5 - sqrt(27)) / (25 - 27) =
5 * (5 - sqrt(27)) / 2
well i mean you did write -5*5 but could you simplify that to -25+3 sqrt3?

Answer 6

or would it be -25-15sqrt3/2?

Answer 7

(-5) * (5 - sqrt(27)) / (25 - 27) =
= (-5) * (5 - sqrt(27)) / (-2) =
= 5 * (5 - sqrt(27)) / 2

I made several steps together. It may be confusing..

Answer 8

And yes, you can simplify that:
5 * (5 - sqrt(27)) / 2 = (25 - 15*sqrt(3)) / 2
but I don't think it's a big difference..

Answer 9

ok thank you very much!