Question

The angle of elevation of a tower from a distance 100m from its foot is 60 degrees. Find the height of the tower.

Answer 1

\[\tan \theta= \frac {opp.side}{adj.Side}\]
\[\tan 60= \frac{h}{100}\]
\[\sqrt{3}= \frac {h}{100}\]
\[h=100\sqrt{3}\]

Answer 2

\[100 \text{ Tan }[60{}^{\circ}]=100 \sqrt{3}=173.2 m \]

Answer 3

Even I got this answer, but in book, it is given as " 100/ root 3".

Answer 4

Notify the book publishers.