How will we solve this?? (3/x)+ (3/(x+1) - (3)/(x+2) please explain how to get the new denominator and any restrictions..thanks
you need the same factors in the denominator... what would you do if you had 1/3+ 1/5?
multiply 1/3 by 5 and 1/5 by 3
exactly.. just do the same
so the denominator would have x(x+1)(x+2)
\[(\frac{3}{x} \times \frac{(x+1)(x+2)}{(x+1)(x+2)})+(\frac{3}{x+1} \times \frac{x(x+2)}{x(x+2)})-(\frac{3}{x+2}\times \frac{x(x+1)}{x(x+1)})\]
*trying to absorb this*
oooh i see whats going on...
can we simplify this to this --> 3(x^2 +4x+2)/ x(x+1)(x+2)
dont let the binomials scare you.. they are just factors... oh and unless there is a equal sign suggesting an equality you are not solving for any unknown
there is no equal sign? does that mean i have to solve for the unknown?
i wouldnt think so.. you are just following the instructions given for the problem.. ie simplify or whatever they want you to do
it says mention if there are any restrictions?
from what i remember..restrictions were where you had to plug in 0 in the denominator?!?
the denominator should not be equal to zero
\[x \cancel{=} 0,-1,-2\]
right
ooh..ok...
i got it...
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