Question

Probability distribution ~ Someone willing to help?

Answer 1

question

Answer 2

The independent variables X and Y have the following probability distributions:

X

0=0.3
1=0.2
2=0.4
3=0.1

Y

3=0.5
4=0.2
5=0.3

The sum of one random observation of X and one random observation of Y is denoted by Z.

(a) obtain the probability distribution of Z
(b) Show that E(Z)= E(X) +E(Y) and Var(Z)= Var(X) + Var(Y)

Answer 3

I found (a) just now.

Answer 4

You used the table distribution method.

Answer 5

(a) 3=0.15
4=0.16
5=0.33
6=0.19
7=0.14
8=0.03

Answer 6

I am finding it highly ironical that u asked the question and only u r answering and u are being given medals too, LOL

Answer 7

LOL. I know. I tried forever to answer it.. but I finally got it, and thought everyone who was looking at the question, should know how to get the answer too :) More knowledge it better than none!

Answer 8

I still don't know how they got part B though. I don't think the mean of the frequencies in Z add up to the total mean frequencies in X and in Y. Can someone cross-check perhaps?

Answer 9

find the mean and variance of all 3 random variables

Answer 10

or just prove it in general

Answer 11

Yup. The mean for Z= 5.1. Oh! I see Thanks! Made a stupid mistake!

Answer 12

what is the "table distribution" method?

Answer 13

oh nvm