Question

can anyone help me with this ?
lim x approach 2 ( (x^2 -4)^3 cos (π/x+2) )

Answer 1

0

Answer 2

how ? can you show me how you can get zero? Are you sure ?

Answer 3

if you put 2 for x, you get (2^2-4)cos(pi/2+2)

Answer 4

so you have 0*cos(pi/2+2)

Answer 5

and result is 0

Answer 6

I'm so sorry but I put wrong question. It should be x approach -2, not 2. if then do you know how to do it ?

Answer 7

its the same: put -2 for x and you will get 0*(cos/-2+2)

Answer 8

and its 0 again

Answer 9

we cannot do that since cos ( π/ 0 ) is not zero. we will get math error for that

Answer 10

it is cos(pi/(x+2)) or cos(pi/x+2) ?