Question

Essay; show all work. Add the following polynomials: (1/10x^2 - 1/2x - 3/10) + (1/2x^2 + 1/4x - 1/5)

Answer 1

1/10x^2 - 1/2x - 3/10 + 1/2x^2 + 1/4x - 1/5=

Answer 2

how did you get that could you show me

Answer 3

1/10x2 +1/2x2 -1/2x +1/4x -3/10 -1/5 =
1+5 -2+1 -3-2
= ------ + ------ + ----- =
10x2 4x 10

= 6/10x2 -1/4x -5/10 =
= 3/5x2 -1/4x -1/2

- so i think that x need to be just in numerators but indifferent the resultes are the same

Answer 4

right ?

Answer 5

right

Answer 6

ok thanks good luck bye

Answer 7

do you understand it sure ?

Answer 8

this is the answer I got if you would like to compare

Answer 9

(1/10x^2 – 1/2x(-3/10))+(1/2x^2+(1/4x)(-1/5))
= (1/10)x^2 +(3/20)x + (1/2)x^2 - (1/20)x
= (1/10)x^2 +(3/20)x + (5/10)x^2 - (1/20)x
= (6/10)x^2 + (2/20)x
=(6/10)x^2 + (1/10)x
Find the product: (1/3x^2-2/3)*(1/2x -1/2)
= (1/3)(x^2-2)(1/2)(x-1)
= (1/6)(x^3-x^2-2x+2)