Question

the average of two numbers,a and b is given by:a=a+b/2 if the average is 95 and number is 88 what is the other number? please show all of your work.

Answer 1

your question is slightly misleading, the average is given by:\[average=\frac{a+b}{2}\]

Answer 2

you have stated it as:
a = a+b/2

Answer 3

the "a" on the left of the equation is not the same as the "a" on the right hand side

Answer 4

(a+b)/2=95

Lets say a=88

(88+b)/2=95

Solve for b
Multiply both sides by 2
88+b=190

Substract both sides 88

b=102

That is your other number.

Answer 5

so you just need to rearrange the equation to find "a" or "b" as follows:\[a+b=2*average\]\[a=(2*average)-b\]put in the values you are given to find "a".

Answer 6

can i get some more HELP

Answer 7

I already answere the question.

You got that

A=(a+b)/2

A=95
Any of a or b can be 88

So lets make a=88

Replacing

95=(88+b)/2

Multiply both sides by 2

190=88+b

Substract both sides 88

102=b

Thats your answer.

Answer 8

WHERE DID YOU GET 95 FROM AND Y DID REPLACE THE A ON THE OUT OF THE EQUAL SIGN IT JUST NOT LOOKIN RIGHT THE ON THE OUTDSIDE NEVER CHANGE

Answer 9

A=A+B/2

Answer 10

WE SOLVING FOR A +B NOTHING ELSE

Answer 11

A=Average

a=firts number

b=second number.

Your question says.
if the average is 95 and number is 88 what is the other number?

Son replacing.

A=95
a=88
b=?

Answer 12

IM SORRY THE AVERAGE IS 93 I MESS THAT UP

Answer 13

You got that

A=(a+b)/2

A=93
Any of a or b can be 88

So lets make a=88

Replacing

93=(88+b)/2

Multiply both sides by 2

186=88+b

Substract both sides 88

98=b

Happy?

Answer 14

HAPPY THANKS