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Mathematics 23 Online
OpenStudy (anonymous):

Arcsin(sin(3pi))

OpenStudy (anonymous):

Sin 3pi is 0. Thus Arc sin(0) is 0 or in reallity any mulitpl of pi

OpenStudy (ash2326):

arcsin(sin3pi) arcsin(sinx) is x only when x lies between -pi/2 to pi/2 sin 3pi=0 arcsin (0)=0 so 0 is the answer remembert the range of arcsin is -pi/2 to pi/2

OpenStudy (anonymous):

Thanks Ash

OpenStudy (anonymous):

And Lag

OpenStudy (anonymous):

i dont understand how acrsin(sin(3pi))=3pi=0 . its said that the range of acrsin is -pi/2<y<pi/2 which lies between quadrants 1 and 4. if 3pi lies in the x-axis between quadrants 2 and 3, then how is 3pi in the range of arcsin? thus how is the answer 0 ? please help

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