Question

What is the solution set (ordered pairs) for this inequality? y ≤ x + 2

Answer 1

first graph the boundary line y = x+2

Answer 2

then pick a point that is clearly NOT on the line; like 0,0 and see if its good or bad

if good, use that side, if bad, use the other side

Answer 3

since: 0 <= 0+2 is true; we shade the side the has (0,0) in it

Answer 4

i spose the x>= and y<= would satisfy the solution sets

Answer 5

{(x,y): x>= -2, y <= 2}

something like that

Answer 6

I can choose from..(there ca be more than one answer..)

(-1, 1)
(0, 3)
(2, 4)
(3, 2)

Answer 7

well, given options to choose from, its tends to be simpler to just plug them in and see what fits :)

Answer 8

y <= x + 2
1 -1
------------
1 <= -1+2 is true


y <= x + 2
3 0
----------
3 <= 0+2 is false



y <= x + 2
4 2
-----------
4 <= 2+2 is true


y <= x + 2
2 3
----------
2 <= 3+2 is false

Answer 9

You lost me there lol

Answer 10

i just pluged in the values for (x,y) that they gave us to see what rang true

Answer 11

Which ones were true?

Answer 12

well, seeing that i tried them in order .... id say the ones that are marked true :)

Answer 13

so (3,2) and (2,4) are true?

Answer 14

(-1, 1) T
(0, 3) F
(2, 4) T
(3, 2) F

im pretty sure i did the math right ... you might wanna dbl chk it tho

Answer 15

It was right thanks :)

Answer 16

yay!! :) good luck