Question

solve log(v-1/v-16)=2

Answer 1

i gotta know the steps to do it on paper

Answer 2

log base ten, so what we could do is simply:
raise both sides to 10, thereby elminating the log: and leaving us with:
(v-1/v-16)=10^2
then im sure you can isolate v byyourself

Answer 3

i get 1599/99 as my answer but the correct answer is 533/33

Answer 4

\[\log(v-1)=2+\log(v-16)\]
\[\log(v-1)-\log(v-16)=2\]
\[\log \left(\begin{matrix}v-1 \\ v-16\end{matrix}\right)=2\]
\[v-1=100v-1600\]

Answer 5

thats what i did

Answer 6

okay, so whats the problem

Answer 7

v=100v-1599
99v=-1599
v=1599/99

Answer 8

\[99v=1599 =1599/99 so its \not 533/33\]

Answer 9

yeah

Answer 10

but the answer is 533/33