Question

SHM HELP

Answer 1

Aravind, write out your problem. Use the equation editor if needed.

Answer 2

1.When a mass m is attached to a spring it normally extends by 0.2 m .The mass m is given a slight additional extension and released ,then its time period is??

Answer 3

help

Answer 4

so there is no damping force?

Answer 5

m x'' + k x= f(t)

Answer 6

I don't think he wants the DE's

Answer 7

ya i am only in high scool

Answer 8

options:
a)1/pi b)2pi/7 c)7 d) 1/7

Answer 9

x'' + k/m x= 0

r^2=- k/m
complex root

x= cos(Sqrt[k/m]t )

angular frequency = Sqrt[k/m]

freqency= Sqrt[k/m]/2pi

period= 2pi/ Sqrt[k/m]= 2pi Sqrt[m/k]

Answer 10

Yes, period
\[ T = 2\pi \sqrt{m/k} \]
So you need to know the spring constant k and the mass m.

Answer 11

how??

Answer 12

only this much info in qn

Answer 13

pls try there must be a way use .2 m

Answer 14

oh, ok, yes. If the system is at rest at 0.2 m, what can we say? We can say that the forces cancel:
Spring force on mass = Gravitational force on mass
kx = mg
0.2k = 9.8m
=> k/m = 9.8/0.2 = 49

Now use that to find your period.

Answer 15

wow thx i hav some more qns dont go away

Answer 16

20.A loaded spring vibrates with a period T .The spring is divided into 4 equal parts and the same load is suspended from one of these parts ,The new period is??

Answer 17

If the original spring had constant k, what is the spring constant of the new springs?

Answer 18

k/4???

Answer 19

yes. now you figure out what that does to your T. Use the formula
\[ T = 2\pi \sqrt{m/k} \]

Answer 20

2T RYT??

Answer 21

:)

Answer 22

yep

Answer 23

NEXT ONE

Answer 24

21.A mass is suspended by 2 spring constants k1 and k2 connected in parallel as shown in fig The time period T of vibrations of M in vertical direction is??