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1+COTX+COSECX\1+COTX-COSECX=COTX+COSECX JUST PROVE IT
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draw it
\[{1+\cot(X)+ cosec(X) \over 1+\cot(X)-cosec(X)}= = \cot(X)+cosec(X) \] is that right?
i don't think they are the same?
They are not equal...a counterexample is pi/2 cot(pi/2) = 0, cosec(pi/2) = 1 --> 2/0 = 1, which is False
write cotx = (cosx)/(sinx)
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