Question

1+COTX+COSECX\1+COTX-COSECX=COTX+COSECX JUST PROVE IT

Answer 1

draw it

Answer 2

\[{1+\cot(X)+ cosec(X) \over 1+\cot(X)-cosec(X)}= = \cot(X)+cosec(X) \] is that right?

Answer 3

i don't think they are the same?

Answer 4

They are not equal...a counterexample is pi/2

cot(pi/2) = 0, cosec(pi/2) = 1

--> 2/0 = 1, which is False

Answer 5

write cotx = (cosx)/(sinx)