Question

A cargo plane flew to the maintenance
facility and back. It took one hour less time
to get there than it did to get back. The
average speed on the trip there was 220
mph. The average speed on the way back
was 200 mph. How many hours did the trip
there take?

Answer 1

yeah its a hard one

Answer 2

the answer is 10 hours but i don't know how to work that problem

Answer 3

i just have the answers and quizzing myself

Answer 4

We know:
Speed(to) = 220
Time(to) = x hours

Speed(back) = 200
Time(back) = x+1 hours

Speed = Distance / Time => Distance = Speed * Time
Distance is same so equations for distance(to) and distance(back) can be equated so that:

Speed(to) * Time(to) = Speed(back) * Time(back)

220*x = 200*(x+1)
220x = 200x + 200
220x - 200x = 200
20x = 200
x = 10

Therefore:
Time(to) = x = 10 hours
and
Time(back) = x+1 = 10+1 = 11 hours.

Answer 5

would d=220(x-1) have been sufficient?

Answer 6

I wouldn't think so, you'd have to get the numerical answer as it is possible.

Answer 7

Do you understand how to get it from what I've put?

Answer 8

i think so

Answer 9

yeah i do thank you that was brilliant!

Answer 10

No probs mate!