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Mathematics 18 Online
jhonyy9 (jhonyy9):

- so if the complex number is in the form of a+ib , where a is the real part and ib is the imaginary part - so if this is right ,than please write me that in the Riemann hypothesis formula what is 1/2 +it ,so than if 1/2 is the real part ,than ,,it" is the imaginary part ? - and from this what is t ?

jhonyy9 (jhonyy9):

why ? from it what is t ?

jhonyy9 (jhonyy9):

just one coeficient of i ?

jhonyy9 (jhonyy9):

or what ?

jhonyy9 (jhonyy9):

like from a+ib - so in case of ib part what is b ?

jhonyy9 (jhonyy9):

angela can you write me ? please

jhonyy9 (jhonyy9):

- so how do you think it please i see it true ?

OpenStudy (angela210793):

I'm sorry idk Riemann formula...When I was in hs we didn't work too much on complex no.s...just the basics :( Sorry can't help u :(

jhonyy9 (jhonyy9):

ty. but if you check it on wikipedia there is write that is formula 1/2 + it

jhonyy9 (jhonyy9):

where it is the imaginary part

OpenStudy (angela210793):

http://en.wikipedia.org/wiki/Riemann_sum this is wht wikipedia says abt Riemann...I've never heard of him before...

OpenStudy (angela210793):

u know...i think b can be any real number....not sure wht u're talking abt though :(

OpenStudy (mathmate):

a+ib, where i^2=-1 a and b are real numbers. So in the case of 1/2+it t is assumed to be a real number, and "it" together form the imaginary part.

jhonyy9 (jhonyy9):

ty

jhonyy9 (jhonyy9):

i have thought it the same too

OpenStudy (mathmate):

Good! You're welcome!

jhonyy9 (jhonyy9):

so can you help me again how have formed the riemann"s zeta functions graphed

OpenStudy (mathmate):

Do you mean this? http://en.wikipedia.org/wiki/File:Zeta_polar.svg You're better off posting a new post so your question doesn't get buried here.

jhonyy9 (jhonyy9):

ok check it now ty

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