Question

See attachment.

Answer 1

Try multiplying top and bottom by \((\sqrt{a}-\sqrt{b})\).\[\]

Answer 2

you get \[(\sqrt{a}+\sqrt{b})^{2}/a-b\] by using across's method, which does rationalise the denominator

Answer 3

so is that the answer?

Answer 4

The plus at the top should be a negative, but that's the correct answer.

Answer 5

So is this the answer?
\[\left(\begin{matrix}(\sqrt{a}-\sqrt{b})^{2} \\ a-b\end{matrix}\right)\]

Answer 6

??????