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verify the identity sec x- cos x = sin x tan x
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1) Redefine secx using Reciprocal Identity \[1/\cos x-\cos x=\sin x \tan x\] 2) LCD (Least Common Denominator) \[(1-\cos ^2x)/\cos x=\sin x \tan x\] 3) Use the Basic Identity sin^2x + cos^2x = 1 \[\sin ^2x/\cos x\] 4) Factor out \[(\sin x)(\sin x/\cos x)\] 5) Use the identity of tangent \[(sinx)(\tan x)\] VERIFIED. :) You can also try to manipulate using the right hand side of the equation. When proving, NEVER use both sides. One at a time. (Though there are cases that you'll prove using both sides)
\[ \sec x- \cos x = \frac{1}{\cos x} - \cos x = \frac{\sin^2 x }{\cos x} =\sin x \times \tan x \space \space [QED]\]
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