Question

Newton’s universal law of gravitation says that the force of gravitational attraction, F
between two particles is directly proportional to the product of their masses, 1 m and
2 m , and inversely proportional to the square of the distance, d , between them.
If the two particles each lose half of their mass as the distance between them triples,
how would the gravitational attraction between them change

Answer 1

\[-G \frac{Mm}{r^2}\]

Answer 2

so let's do what problem say

\[-G \frac{(1/2M)(1/2m)}{(3r)^2}\]

Answer 3

\[-G \frac{(1/2M)(1/2m)}{(3r)^2}=-G \frac{1/4(M)(m)}{9(r)^2}=-G ((1/4) /9)\frac{(M)(m)}{(r)^2}\]

Answer 4

can you wxplain please

Answer 5

I took the gravity equations

\[-G \frac{Mm}{r^2}\]


and your problem states
"If the two particles each lose half of their mass as the distance between them triples,"

so that's what I did

\[-G \frac{(1/2M)(1/2m)}{(3r)^2}\]

and I simplified it

\[-G ((1/4) /9)\frac{(M)(m)}{(r)^2}= \frac{1}{36}(-G \frac{Mm}{r^2} )\]

Answer 6

so gravitation force change by 1/36

Answer 7

Better now sorry its just confusing. great work

Answer 8

so main thing is changing each part and noticing how it affects the whole thing