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OpenStudy (anonymous):
Calculate the mass of chloroform that contains 1.00x10^12 molecules of CHCl3
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OpenStudy (anonymous):
\[1.00x10^23 molec CHCl_3(\frac{1 mole }{6.022x10^23 molec})(\frac{119.37 g }{1 mole})\]
OpenStudy (anonymous):
Awesome, thank you
OpenStudy (anonymous):
I have a typo in my equation it should b 1.00x10^12
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