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Chemistry 16 Online
OpenStudy (anonymous):

Calculate the mass of chloroform that contains 1.00x10^12 molecules of CHCl3

OpenStudy (anonymous):

\[1.00x10^23 molec CHCl_3(\frac{1 mole }{6.022x10^23 molec})(\frac{119.37 g }{1 mole})\]

OpenStudy (anonymous):

Awesome, thank you

OpenStudy (anonymous):

I have a typo in my equation it should b 1.00x10^12

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