TuringTest, want to continue?
lol I like the attitude, I better eat though, give me a bit what time is it where you are?
9:45 pm, you? Then go eat :)
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factor 21x^2+14x
GCF of 21 and 14=7 GCF of x and x^2 is x 21x^2/7x+14x/7x=x(3x+2)?
almost but 1)be careful of notation 21x^2/7x+14x/7x is not equal x(3x+2) 2) remember to keep the whole GCF outside the parentheses
But i thought that if the 7 was on the LHS then it couldnt be on the RHS?
21x^2/7x+14x/7x=7x(3x+2)?
but they are not equal 21x^2/7x+14x/7x=3x+2 not 7x(3x+2) so you must write 21x^2+14x=7x(21x^2/7x+14x/7x)=?
I dont know...
7(3x^2+2)?
you almost have it but you need to put the GCF outside the parentheses what is the GCF?
7x
so that's what goes outside the parentheses
7x(3x^2+2) Cant be right.
what is 21x^2/7x=? rewrite it in a way more comfortable to you if it looks strange
21/7 * x^2/x?
yes...
Im pretty sure thats 3x man
it is, so why did you write 3x^2 above?
Cause you said the other one wasnt right :/ What is the correct way to write it?
here was your first answer x(3x+2) here was the next 21x^2/7x+14x/7x=7x(3x+2) the answer here is correct, I just pointed out that the two expressions above are not equal, I think that may have confused you. next you wrote 7x(3x^2+2) so I think we started to get off track... the answer is 21x^2+14x=7x(3x+2) I just made a point about how you show your work, and what it means.
Ohhhhh :)
write out the process as 21x^2+14x=7x(3x)+7x(2)=7x(3x+2) that is really the best way to show factoring
Oh ok :D Another one?
factor 3t^3+9t^2
sorry, so you know how to divide t^3/t^2 ???
x*x*x ----- right? It should jjust become x? x*x
t, sorry
you got it, so my question stands: factor 3t^3+9t^2
GCF of 3 and 9 is 3. GCF of t^2 and t^3 is t. 3t^3+9t^2=3t(3t^3/3t)+3t(9t^2/3t)=3t(t^3+3t^2)?
check your answer and distribute to see if you get the original: \[3t(t^3+3t^2)=3t(t^3)+3t(3t^2)=3t^4+9t^3\neq3t^3+9t^2\]you didn't divide the terms in the middle right ...but I think more importantly the GCF of t^3 and t^2 is t^2, not t that is because each term can be evenly divided by t^2.
Hm
Oh right!
what is the GCF of t^3+t^5+t^7 ??
Something to the power of something doesnt follow the rules of usual numbers, forgot that. It should be t^5
no it's t^3 and it does follow the rules of regular numbers if you think about it, otherwise it wouldn't be true! look at 16,32,8 what is their GCF ?
8
now rewrite those three numbers as powers of 2
can you do that?
256,1024,64
?
no I meant like 8=2^3 16=2^? 32=2^?
Oh! 8=2^3 16=2^4 32=2^5
...and what is their GCF? 2^3 so the GCF of a set of variables is the highest common power to each term -in this case 3 so if we have y^4+y^7+y^9 the GCF is...?
y^4?
right :)
:D
good job :D so now back to our question... factor 3t^3+9t^2 what is the GCF?
3t^2?
right now can you factor it?
3t^3+9t^2=3t^2(3t^3/3t^2)+3t^2(9t^2/3t^2)=3t^2(t+3)?
very nice!!!!!!
I got it!! :D
you totally did :D that is very cool! so now lets see what's so great about factoring say we have f(t)=3t^3+9t^2 and we want to know the 'zeros' of the function that means when the function touches the x-axis, i.e. when f(t)=0 so to answer this we must solve 0=3t^3+9t^2 how can we solve that? by factoring... 0=3t^2(t+3) now you can solve it quickly, any idea which fundamental rule of algebra tells us how?
Nope, sorry
the rule is called the 'zero factor property' it states that if\[ab=0\]then either\[a=0\]or\[b=0\]or both does this rule make logical sense to you?
Yeah
so now look at our factored equation \[0=ab=3t^2(t+3)\]that means that either\[3t^2=0\]or \[t+3=0\]can you solve each of these equations?
*either or both I should say
OH so 3t^2 represents a and t+3 represents b!
exactly that's why i said to learn the rules on this page http://www.capitan.k12.nm.us/teachers/shearerk/basic_rules_of_algebra.htm almost all of algebra is in there, though sometimes it is hidden
3t^2=0 t=0-3t/t t=0-3 t=-3?
no, it's more simple than that, remember the same rule we just used: ab=0 then either a=0 or b=0 or both 3t^2=0 let 3=a t^2=b we know that a=3 cannot be zero, because 3 is never zero, it's a constant that leaves the possibility only of t^2=0 and the number number that times itself is zero is zero so\[3t^2=0\to t=0\]
Ohhhh.. Cause 3x0x0=0?
right so t has to be zero...
Yeah
what about the other possibility t+3=0 ???
How can that be possible when t is 0?
there are two answers to every quadratic equation as you may recall me saying this is cubic so it has 3 actually, we say that zero ocurrs twice in 3t^2=0 because it leads to two 0's as you showed: 3x0x0 we call that a 'multiplicity of 2' so there will be multiple answers, the other is found by solving t+3=0 remember that either a=0 or b=0 or BOTH we don't know so we have to solve them all.
Oh right! This is a quadratic equation. t=-3 on this one so its (0,-3)?
like I said, cubic read what I wrote above please about multiplicity...
Three answers
So these are cubic coordinates?
(0,0,-3)?
not cubic coordinates (I don't know what that is exactly...), it's just that we say that 3t^3+9t^2 has zeros (0,3) - that means the graph of f(x)=3t^3+9t^2 hits zero there... where 0 here has a 'multiplicity' of 2 (that means it occurs twice) and 3 has a multiplicity of 1
So why isnt -3 involved?
sorry typo, meant (0,-3)* and -3 has multiplicity 1*
good catch
Thanks
so do you see what I mean? the zero's of\[f(t)=3t^2+9t^2\]are found by factoring and setting to zero\[0=3t^2(t+3)\]then solving each possibility\[3t^2=0\to t=0\]\[t+3=0\to t=-3\]where we say that for t=0 k=2 and for t=-3 k=1 where k is the multiplicity
Right, the k is cause t is to the power of 3 there.
for the part that had 3t^2=0 we had k=2 (because zero is the answer twice: 3x0x0) for t+3=0 we have k=1 because t is only to the first power and we only have one answer If what you mean is that you noticed that adding up all the k's gave youu 3, the order of the cubic, then you have noticed what is called the Fundamental Theorem of Algebra: "The sum of the multiplicities of the roots of a function is equal to the order of the polynomial" \[k_0+k_{−3}=2+1=3\]
- a very important theorem as the name implies...
I dont really get the theorem, please explain it.
Basically for whatever the highest power variable you have in a polynomial, that is how many answers you have. Note that they may not be all different answers, but the ones that occur more than once are counted as having a higher multiplicity, so if you add up the multiplicities (the k's) that's how many zeros the polynomial has. for example 7x^5+3x^3+2x^2+5x+3=0 must have 5 answers, because it is 5th order x^2+2x+2=0 must have 2 answers, because it is second order
So x^4+5x-4=0 must have 4 answers?
exactly, though it may not be 4 different answers for instance x^4=0 has only the answer x=0, but that zero has a multiplicity of k=4 because 0x0x0x0=0 is how it must be...
Oh, now i get it
good :) do you want to try some more factoring problems? or perhaps you should learn a little about exponents first? or perhaps you are ready top get some rest.... which is it?
I wanna learn something new :D
let's see if this is news to you: simplify\[{x^{14}\over x^{12}}\]
x^2 lol
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