Question

simplify completely x^2+12-x/x^2-x-20 divided by 3x^2-24x+45/12x^2-48x-60

Answer 1

\[(x^2-x+12)/((x-5) (x+4)) \div(x-3)/(4 (x+1))\]

Answer 2

what does that even mean?

Answer 3

the first equation is siplified to\[ x^2+12-x/x^2-x-20 = (x^2-x+12)/((x-5) (x+4)) \]

Answer 4

the second equation..ii\[3x^2-24x+45/12x^2-48x-60=(x-3)/4(x+1)\]

Answer 5

are you asked to solve completely ?

Answer 6

yes please

Answer 7

Which therefore equals\[(x^2-x+12)4(x+1)/(x-5)(x+4)(x-3)\], to intrude humbly.

Answer 8

the answers are x+1/8(x-5), 8(x-5)/x+1, 4(x+1)/x-5 or x-5/4(x+1)

Answer 9

PLEASE HELP :(

Answer 10

i forgot the parenthese again lol

Answer 11

First fraction
is what you wrote correct --> x^2+12-x ???? This does not factor and I would expect it to

Answer 12

no x^2+x-12 i mean that

Answer 13

got it,
now first fraction numerator factors to (x+4)(x-3)
its denominator factors to (x-5)(x+4)
and the (x+4) cancels

Answer 14

for the second fraction the numerator factors to 3*(x-3)(x-5)
and the denominator factors to 12*(x+1)(x-5)
and the (x-5) cancels and 3/12 reduces to 1/4
So we have (x-3)/[4*(x+1)]

Answer 15

Now since we are dividing, we want to flip the second and multiply across
New numerator is 4*(x-3)(x+1)
New denominator is (x-5)(x-3)

and the (x-3) cancels

You are left with [4*(x+1)]/(x-5)

Answer 16

if the input you gave was correct then the simplified form should be\[4(x+1)/(x-5)\]

Answer 17

Okay i kinda get it now thanks guys!

Answer 18

no stress!

Answer 19

do you guys get to higher levels by answering questions?