Determine the nature of the solutions of the equations.
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OpenStudy (anonymous):
\[y^{2}={5\over6}y+{1\over2}\]
OpenStudy (anonymous):
a. the equation has one real solution
b. the equation has two non-real solution
c. the equation has two real solutions
OpenStudy (anonymous):
c. the equation has two real solutions
OpenStudy (anonymous):
is this correct?
OpenStudy (turingtest):
I'm not getting that
how did you check it?
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OpenStudy (anonymous):
I solved the problem
OpenStudy (turingtest):
all you need to do is check the discriminant
do you know what that is?
OpenStudy (akshay_budhkar):
@Turing as far as I know yes .. the asker knows about it.. it is just asking to confirm it is right..
The answer is you are correct.
OpenStudy (turingtest):
Oh I'm sorry you're right "P
OpenStudy (anonymous):
b^2 - 4ac
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OpenStudy (anonymous):
ok tytytyty
OpenStudy (turingtest):
Sorry my mistake...
Yes I made c positive...
alas I am human :(
OpenStudy (anonymous):
ok, i'll be back. tytytytyty
OpenStudy (akshay_budhkar):
turing made a mistake? Rare happening indeed! i thought you were a PC :d
OpenStudy (turingtest):
The ultimate proof of humanity... I told you I make mistakes
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OpenStudy (akshay_budhkar):
@turing would u mind me asking you what course are you taking ( i may take help from you if we are in same course)
OpenStudy (turingtest):
Thanks but unfortunately I am in calculus officially (again) but through my own studies have covered a fair amount of differential equations.
It's a long story... but I can help you in the multivariable I happen to know.
OpenStudy (akshay_budhkar):
i thought you were in some engineering course
OpenStudy (akshay_budhkar):
your knowledge is vast :D
OpenStudy (anonymous):
no 8th grade quiz
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OpenStudy (anonymous):
Give exact and approximate solutions to three decimal places.
OpenStudy (turingtest):
I am between countries at the moment, but my own studies are outside the realm of courses I have taken. I hope to get into a solid engineering school soon, right now it is fairly remedial.
OpenStudy (anonymous):
\[x^{2}+7x-3=0\]
OpenStudy (anonymous):
a. x = 0.405 and x = 7.405
b. x = 0.41 and x = 7.41
OpenStudy (anonymous):
are these answers correct?
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OpenStudy (akshay_budhkar):
We are in same boat turing !!!!!!! i was in the same situation. i was between countries sigh, so my situation is similar to yours
OpenStudy (akshay_budhkar):
@notebook, what did you get as your answer?
OpenStudy (anonymous):
a and b are my answers
OpenStudy (anonymous):
a. is approx
b. is exact
OpenStudy (turingtest):
b. cannot be exact, how do you figure so?
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OpenStudy (anonymous):
b is rounded to the nearest number
OpenStudy (akshay_budhkar):
almost correct... it should be -7.405
and a. is exact
b. is approx which is rounded
OpenStudy (anonymous):
phew, thx i missed that.
OpenStudy (turingtest):
if you want exact you have to keep it in the square root format, because sqrt{49+4*3) is irrational
OpenStudy (turingtest):
...so no rounding
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OpenStudy (anonymous):
the quiz asked for approximate and exact
OpenStudy (akshay_budhkar):
so exact is what turing says approx is b
OpenStudy (anonymous):
the width of a rectangle is 1 ft less than the length. the area is \[30 ft ^{2}\]. Find the length and the width.
OpenStudy (anonymous):
a. Length = 5
b. Width = 6
OpenStudy (anonymous):
is this correct?
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OpenStudy (akshay_budhkar):
nope a silly error!! read again
OpenStudy (turingtest):
I beleive it is correct, but let akshay check
OpenStudy (akshay_budhkar):
width is 1 feet LESS than the length... not MORE
OpenStudy (anonymous):
i'm sorry i mixed the answers up
I do have w = 5 L= 6
OpenStudy (anonymous):
sorry about that.
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OpenStudy (akshay_budhkar):
:D
OpenStudy (turingtest):
oh I didn't look at that bit... Just saw the numbers :P
OpenStudy (akshay_budhkar):
lol and u made me look at the question 5 times ! :P
OpenStudy (turingtest):
teach you not to trust me!
got any more notebook?
OpenStudy (akshay_budhkar):
i trusted you, trust you and will trust you :P :P
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OpenStudy (anonymous):
Find and label the vertex and the line of symmetry. Graph the function.
\[f(x)=(x+2)^{2}\]
OpenStudy (anonymous):
vertex = (-2,0)
symmetry is x = -2
OpenStudy (turingtest):
yes
OpenStudy (anonymous):
tytytytyty
OpenStudy (turingtest):
thank you for trying :)
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OpenStudy (akshay_budhkar):
you are done?
@Turing hope to talk to you soon :D
OpenStudy (turingtest):
Likewise, though I don't know what I have to say
more notebook?
OpenStudy (anonymous):
Solve by completing the square.
OpenStudy (anonymous):
\[m ^{2}-{9\over2}m={3\over2}\]
OpenStudy (anonymous):
let me answer, first. one moment
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OpenStudy (anonymous):
\[m=-9+\sqrt{105\over4} or -9-\sqrt{105\over4}\]
OpenStudy (turingtest):
not what I'm getting, I'll show...
OpenStudy (akshay_budhkar):
silly mistake again
i am getting
\[(9\pm \sqrt{105})/4\]
OpenStudy (anonymous):
I don't have the option of using the ± sign
OpenStudy (turingtest):
yes that's it...
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OpenStudy (anonymous):
phew, tyutytytyty
OpenStudy (turingtest):
the four is or is not under the square root?
OpenStudy (akshay_budhkar):
Not
OpenStudy (turingtest):
should not be, I'm trying to point out the difference to notebook
hers is
OpenStudy (anonymous):
ok. i get it.
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OpenStudy (akshay_budhkar):
so can we take a leave?
OpenStudy (anonymous):
i looked over the examples and it's like that in the examples
OpenStudy (akshay_budhkar):
nope, it shouldn't be.. 4 doesnt come in the root, it must be a mistake
OpenStudy (anonymous):
ok
OpenStudy (akshay_budhkar):
you got anything else?
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OpenStudy (anonymous):
oh yea
OpenStudy (akshay_budhkar):
go ahead then
OpenStudy (anonymous):
Solve\[3x ^{2}=21\]
Find the x-intercepts of \[f(x)=3x ^{2}-21\]
What are the solutions?
What are the x-intercepts?
OpenStudy (anonymous):
\[(\sqrt{7},0) and (-\sqrt{7},0 )\]
OpenStudy (turingtest):
yep
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OpenStudy (anonymous):
x = 7
OpenStudy (turingtest):
?
OpenStudy (akshay_budhkar):
the first one was correct
OpenStudy (anonymous):
The solutions is x = 7
The x-intercepts are (7√,0)and(−7√,0)
OpenStudy (turingtest):
the solution is\[x=\pm\sqrt7\]
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OpenStudy (akshay_budhkar):
try checking it by resubsituting the value of x that you got in the original equation
OpenStudy (anonymous):
since i don't have the option of using the ± symbol. so i should say \[x=+\sqrt{7} and -\sqrt{7} ?\]
OpenStudy (turingtest):
I guess, sure
OpenStudy (akshay_budhkar):
yes..
OpenStudy (turingtest):
as akshay said look at the fact that this makes it true\[3(\sqrt7)^2=21\]\[3(\sqrt{-7})^2=21\]so there are two answers, however you want to write it
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OpenStudy (anonymous):
Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function.
\[f(x)=9-x ^{2}\]
OpenStudy (anonymous):
vertex is (0,9)
OpenStudy (anonymous):
x=0
OpenStudy (anonymous):
y=9
OpenStudy (anonymous):
Symmetry is x=0
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