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Mathematics 16 Online
OpenStudy (anonymous):

Determine the nature of the solutions of the equations.

OpenStudy (anonymous):

\[y^{2}={5\over6}y+{1\over2}\]

OpenStudy (anonymous):

a. the equation has one real solution b. the equation has two non-real solution c. the equation has two real solutions

OpenStudy (anonymous):

c. the equation has two real solutions

OpenStudy (anonymous):

is this correct?

OpenStudy (turingtest):

I'm not getting that how did you check it?

OpenStudy (anonymous):

I solved the problem

OpenStudy (turingtest):

all you need to do is check the discriminant do you know what that is?

OpenStudy (akshay_budhkar):

@Turing as far as I know yes .. the asker knows about it.. it is just asking to confirm it is right.. The answer is you are correct.

OpenStudy (turingtest):

Oh I'm sorry you're right "P

OpenStudy (anonymous):

b^2 - 4ac

OpenStudy (anonymous):

ok tytytyty

OpenStudy (turingtest):

Sorry my mistake... Yes I made c positive... alas I am human :(

OpenStudy (anonymous):

ok, i'll be back. tytytytyty

OpenStudy (akshay_budhkar):

turing made a mistake? Rare happening indeed! i thought you were a PC :d

OpenStudy (turingtest):

The ultimate proof of humanity... I told you I make mistakes

OpenStudy (akshay_budhkar):

@turing would u mind me asking you what course are you taking ( i may take help from you if we are in same course)

OpenStudy (turingtest):

Thanks but unfortunately I am in calculus officially (again) but through my own studies have covered a fair amount of differential equations. It's a long story... but I can help you in the multivariable I happen to know.

OpenStudy (akshay_budhkar):

i thought you were in some engineering course

OpenStudy (akshay_budhkar):

your knowledge is vast :D

OpenStudy (anonymous):

no 8th grade quiz

OpenStudy (anonymous):

Give exact and approximate solutions to three decimal places.

OpenStudy (turingtest):

I am between countries at the moment, but my own studies are outside the realm of courses I have taken. I hope to get into a solid engineering school soon, right now it is fairly remedial.

OpenStudy (anonymous):

\[x^{2}+7x-3=0\]

OpenStudy (anonymous):

a. x = 0.405 and x = 7.405 b. x = 0.41 and x = 7.41

OpenStudy (anonymous):

are these answers correct?

OpenStudy (akshay_budhkar):

We are in same boat turing !!!!!!! i was in the same situation. i was between countries sigh, so my situation is similar to yours

OpenStudy (akshay_budhkar):

@notebook, what did you get as your answer?

OpenStudy (anonymous):

a and b are my answers

OpenStudy (anonymous):

a. is approx b. is exact

OpenStudy (turingtest):

b. cannot be exact, how do you figure so?

OpenStudy (anonymous):

b is rounded to the nearest number

OpenStudy (akshay_budhkar):

almost correct... it should be -7.405 and a. is exact b. is approx which is rounded

OpenStudy (anonymous):

phew, thx i missed that.

OpenStudy (turingtest):

if you want exact you have to keep it in the square root format, because sqrt{49+4*3) is irrational

OpenStudy (turingtest):

...so no rounding

OpenStudy (anonymous):

the quiz asked for approximate and exact

OpenStudy (akshay_budhkar):

so exact is what turing says approx is b

OpenStudy (anonymous):

the width of a rectangle is 1 ft less than the length. the area is \[30 ft ^{2}\]. Find the length and the width.

OpenStudy (anonymous):

a. Length = 5 b. Width = 6

OpenStudy (anonymous):

is this correct?

OpenStudy (akshay_budhkar):

nope a silly error!! read again

OpenStudy (turingtest):

I beleive it is correct, but let akshay check

OpenStudy (akshay_budhkar):

width is 1 feet LESS than the length... not MORE

OpenStudy (anonymous):

i'm sorry i mixed the answers up I do have w = 5 L= 6

OpenStudy (anonymous):

sorry about that.

OpenStudy (akshay_budhkar):

:D

OpenStudy (turingtest):

oh I didn't look at that bit... Just saw the numbers :P

OpenStudy (akshay_budhkar):

lol and u made me look at the question 5 times ! :P

OpenStudy (turingtest):

teach you not to trust me! got any more notebook?

OpenStudy (akshay_budhkar):

i trusted you, trust you and will trust you :P :P

OpenStudy (anonymous):

Find and label the vertex and the line of symmetry. Graph the function. \[f(x)=(x+2)^{2}\]

OpenStudy (anonymous):

vertex = (-2,0) symmetry is x = -2

OpenStudy (turingtest):

yes

OpenStudy (anonymous):

tytytytyty

OpenStudy (turingtest):

thank you for trying :)

OpenStudy (akshay_budhkar):

you are done? @Turing hope to talk to you soon :D

OpenStudy (turingtest):

Likewise, though I don't know what I have to say more notebook?

OpenStudy (anonymous):

Solve by completing the square.

OpenStudy (anonymous):

\[m ^{2}-{9\over2}m={3\over2}\]

OpenStudy (anonymous):

let me answer, first. one moment

OpenStudy (anonymous):

\[m=-9+\sqrt{105\over4} or -9-\sqrt{105\over4}\]

OpenStudy (turingtest):

not what I'm getting, I'll show...

OpenStudy (akshay_budhkar):

silly mistake again i am getting \[(9\pm \sqrt{105})/4\]

OpenStudy (anonymous):

I don't have the option of using the ± sign

OpenStudy (turingtest):

yes that's it...

OpenStudy (anonymous):

phew, tyutytytyty

OpenStudy (turingtest):

the four is or is not under the square root?

OpenStudy (akshay_budhkar):

Not

OpenStudy (turingtest):

should not be, I'm trying to point out the difference to notebook hers is

OpenStudy (anonymous):

ok. i get it.

OpenStudy (akshay_budhkar):

so can we take a leave?

OpenStudy (anonymous):

i looked over the examples and it's like that in the examples

OpenStudy (akshay_budhkar):

nope, it shouldn't be.. 4 doesnt come in the root, it must be a mistake

OpenStudy (anonymous):

ok

OpenStudy (akshay_budhkar):

you got anything else?

OpenStudy (anonymous):

oh yea

OpenStudy (akshay_budhkar):

go ahead then

OpenStudy (anonymous):

Solve\[3x ^{2}=21\] Find the x-intercepts of \[f(x)=3x ^{2}-21\] What are the solutions? What are the x-intercepts?

OpenStudy (anonymous):

\[(\sqrt{7},0) and (-\sqrt{7},0 )\]

OpenStudy (turingtest):

yep

OpenStudy (anonymous):

x = 7

OpenStudy (turingtest):

?

OpenStudy (akshay_budhkar):

the first one was correct

OpenStudy (anonymous):

The solutions is x = 7 The x-intercepts are (7√,0)and(−7√,0)

OpenStudy (turingtest):

the solution is\[x=\pm\sqrt7\]

OpenStudy (akshay_budhkar):

try checking it by resubsituting the value of x that you got in the original equation

OpenStudy (anonymous):

since i don't have the option of using the ± symbol. so i should say \[x=+\sqrt{7} and -\sqrt{7} ?\]

OpenStudy (turingtest):

I guess, sure

OpenStudy (akshay_budhkar):

yes..

OpenStudy (turingtest):

as akshay said look at the fact that this makes it true\[3(\sqrt7)^2=21\]\[3(\sqrt{-7})^2=21\]so there are two answers, however you want to write it

OpenStudy (anonymous):

Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. \[f(x)=9-x ^{2}\]

OpenStudy (anonymous):

vertex is (0,9)

OpenStudy (anonymous):

x=0

OpenStudy (anonymous):

y=9

OpenStudy (anonymous):

Symmetry is x=0

OpenStudy (anonymous):

downward open be neg coeff

OpenStudy (anonymous):

Max of f(x) = 9

OpenStudy (turingtest):

the max is f(0)=9 yes :) all correct

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