Write a definite integral which can be approximated to be the Riemann Sum of: 1/50 ( sqrt of (1/50) + sqrt of (2/50) + sqrt of (3/50)....sqrt of (50/50) ).
ill write it with teh equation thing also
\[1/50* (\sqrt{1/50} + \sqrt{2/50}+ \sqrt{3/50}...\sqrt{50/50}) \]
you have any idea of where to start?
n=10?
looks like you have 50 to me
\[\sum_{i=1}^{50}\sqrt{\frac{i}{50}}\frac{1}{50}\]
so the function is sqrt of 1/50 times 1/50?
your function is \[f(x)=\sqrt{x}\]
\[\Delta x=\frac{1}{50}\] \[x_i^*=a+i\times\Delta x=\frac{i}{50}\] then you can write the above as \[\sum_{i=1}^{50}f(x_i^*)\Delta x\]
\[\int\limits_{a}^{b}f(x)dx=\lim_{n\to\infty}\sum_{i=1}^{n}f(x_i^*)\Delta x\]
so wat was a in this case? 1?
a=0
b=1
\[\Delta x=\frac{b-a}{n}=\frac{1-0}{50}=\frac{1}{50}\]
srry i cant read that clearlythe limit says as wat approaches infinity?
yes...as n goes to infinity then we get the definite integral
this makes sense now! thanks for explaining teh steps b.c i was confused with how u got the asnwer
srry earler for sum reason i was talkin about another problem which is why i said n = 10 n etc..
the integral you will get in the end is \[\int\limits_{0}^1\sqrt{x}dx\]
why is taht?
look from where I said "your function is \[f(x)=\sqrt{x}\] "
OH!
ok
\[1/50* (\sqrt{1/50} + \sqrt{2/50}+ \sqrt{3/50}...\sqrt{50/50})\approx.676095\] \[\int\limits_{0}^1\sqrt{x}dx=.\overline{6}\]
thats really cool
calc is mucch more fun n interesting when i actually understand it
yep...it's good stuff
i tend to b kinda slow especially wen things arent done step by step...srry
np
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