TuringTest, repetition!
repetition?
You know, practising something you have learned
?
Oh maybe thats not a word xd
revision
factor\[x^2y^4-x^4y^2\]
Ohhh, im thinking of the swedish word..
repetition is a word, just not the right one
Again??
GCF of x^2 and x^4 is x^2 GCF of y^2 and y^4 is y^2 x^2*y^2(x^2*y^4/x^2*y^2)-x^2*y^2(x^4*y^2/x^2*y^2)?
yes that should work :) and yes, /again/ GT lol continue Inopeki.
x^2*y^2(x^2*y^4/x^2*y^2)-x^2*y^2(x^4*y^2/x^2*y^2)=x^2*y^2(y^2-x^2)? Damn thats a long line of numbers!
lol yeah, but you got the right answer :D but I think there's one more thing you can do, look closely.
x^2*y^2(x^2*y^4/x^2*y^2)-x^2*y^2(x^4*y^2/x^2*y^2)=-x^4*y^4?
x^2*y^2(x^2*y^4/x^2*y^2)-x^2*y^2(x^4*y^2/x^2*y^2)=(-x^4)*y^4?
who who you got much closer with x^2*y^2(y^2-x^2) but is there something familiar here?
x^2*y^2(y-x)(y+x)?
yes :) good job, tricky one!
Thanks :DDD
one step closer to quantum mechanics
:D baby steps are still steps, right?
true that :) hey you're going plenty fast you've got time... hmmm do you know how to find the slope of a line give two points?
Yes, if i remember right.
ok (1,4) (6,12) what is the slope between the points?
Well 12+4 ----- Doing alright? 6+1
- actually
gotta subtract, yes the reason for this is important to understand you should think about it if you can
No wait
12-4 ----- =8/5 6-1
right rise over run remember that rise and run are about changes, and to find the change in x or y we must subtract, so it makes sense. what about the equation of the line? any ideas?
\[\Delta y \div \Delta x\]
perfect, even better way to think of it :) now the equation of the line that passes through (1,4) (6,12) do you know how to find that?
|dw:1326067972678:dw|
I need to get x first then substitute to get y?
no, you use the 'Point-Slope' form of the line:\[y-y_1=m(x-x_1)\]where m is the slope (which you have already found) and (x_1,y_1) are the coordinates of one of your points (it doesn't matter which) can you get the equation of the line now?
Wait, 12-4=8/5(6-1)?
no, just use one of the points, the other x and y without subscripts (the little number 1) are just left as x and y...
Oh, y-12=8/5(x-6)?
right, that is the equation in point-slope form there is another form called slope-intercept form that looks like\[y=mx+b\]where b is the y-intercept. Our equation will be in this form if we solve for y, so do that.
y=8/5(x-6)-12?
it would be +12 right? but distribute 8/5 to the parentheses as well to get slope-intercept form.
y=12+(8/5)*(x-6)?
yes now distribute the 8/5...
in order to get rid of the parentheses...
y=12+(8/5)x-6?
you forgot to distribute to the 6...
y=12+(8/5)x-(6)?
(8/5)(x-6) distribute the 8/5 to each term, that is how distribution always works.
a(b+c)=ab+ac
But i did that before!
and what did you get?
Aw man, i need some sleep. school starts tomorrow and its 1:30am XD Im screwed!
lol Thought so... goodnight, good work :)
Goognight! Thanks again for teaching me all this :)
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