Question

i need help !

evaluate the integral dx/sin^2 x + cos^2 x =?

Answer 1

what is that on the bottom?

Answer 2

(sin^2(x)+cos^2(x))?

Answer 3

or just sin^2(x)?

Answer 4

because if it is (sin^2(x)+cos^2(x))?
then this is really easy because sin^2(x)+cos^2(x)=1

Answer 5

I smell an identity here!

Answer 6

(sin^2(x)+cos^2(x))?

Answer 7

eveluate the integral \[\int\limits_{}^{} dx/\sin^2x +\cos^2x\]

that s the question

Answer 8

\[\int\limits_{}^{}(\frac{1}{\sin^2(x)} +\cos^2(x)) dx\]

Answer 9

is that right?

Answer 10

your problem is lacking some parenthesis

Answer 11

\[\int\limits_{}^{} 1/(\sin^2x + \cos^2x)dx\]
that one true

Answer 12

i was assuming at first you meant:
\[\int\limits_{}^{}\frac{dx}{\sin^2(x)+\cos^2(x)} \]

Answer 13

oh yes lol

Answer 14

did you not see what i said above if this what you meant?

Answer 15

\[\sin^2(x)+\cos^2(x)=1\]

Answer 16

\[\int\limits_{}^{}1 dx=x+C\]

Answer 17

oh sorry sorry sin^2 (x) +sinx at the bottom

Answer 18

i reaaly confused

Answer 19

i accidently pressed the back button :(

Answer 20

did u solve ?

Answer 21

i will do it on paper
can't hit the back button there
lol
yeah i was almost done

Answer 22

so just to be sure i'm doing
\[\int\limits_{}^{}\frac{dx}{\sin^2(x)+\sin(x)}\]

Answer 23

lol it s ok. i m waiting...yes be sure. lol i am new member to this site and i don t know many things yet lol

Answer 24

ok done most of it i left one thing for you