Question

PLEASE HELP ME!
3^-3x=17
sole for x using the natural log function

Answer 1

\[-3x=\frac{\ln(17)}{\ln(3)}\] is a start

Answer 2

then
\[x=-\frac{\ln(17)}{3\ln(3)}\]

Answer 3

don't never forget, solve
\[b^x=A\] via
\[x=\frac{\ln(A)}{\ln(b)}\]

Answer 4

what happend to the -3?

Answer 5

in the 2nd step

Answer 6

i divided by it in the second step

Answer 7

i divided by 3, put the minus sign out front

Answer 8

oh i see

Answer 9

so what does x equal?