Question

(sqrt3x-1)^2= (2x)^2 help solve please

Answer 1

\[(\sqrt{3x-1})^{2}=3x-1\]

Answer 2

imaginary roots

Answer 3

So 3x-1 = 4x^2
4x^2-3x+1=0

Answer 4

Now use the quadratic formula.

Answer 5

No, vishal, this doesn't require imaginary numbers because we aren't taking the root of a negative number

Answer 6

Yes we are. since 9-16 is negative.

Answer 7

@mertsj you are right...