OpenStudy (anonymous):

What force, acting for 1.35 x 10^-3 s, changes the velocity of a 95g baseball from 50.0ms^-1 eastward to 45.0 ms^-1 westward?

5 years ago
OpenStudy (underhill):

Newt's 2nd Law:\[Force = mass \times acceleration\] \[Acceleration = \Delta velocity/\Delta time\] \[(V_{final} - V_{initial})/\Delta time = [45.0 - (-50.0)]/(1.35x10^{-3})\] Can you figure it out from here?

5 years ago
OpenStudy (anonymous):

what is 1.35*10^-3?

5 years ago
OpenStudy (anonymous):

.00135?

5 years ago
OpenStudy (underhill):

Yep!

5 years ago
OpenStudy (anonymous):

i got 70370.37 for my answer

5 years ago
OpenStudy (underhill):

In what unit?

5 years ago
OpenStudy (anonymous):

Newtons

5 years ago
OpenStudy (underhill):

Actually no - what you've figured out is the acceleration in meters per second squared. That's the 2nd and 3rd equations in my first post. Great job - you're almost there. Now that you've got the acceleration, how would you get the force? (Be careful - watch your units.)

5 years ago