How do you get this to equal Zero?? -3(x+9)^=-63

Question

myininaya · Answer

the expression looks a bit weird
are you sure this is how it looks?

anonymous · Answer

yes... -_____-

anonymous · Answer

It's squared... the ^ thinggyy? idk. im dumb

myininaya · Answer

no you aren't 
so we have
-3(x+9)^2=-63

myininaya · Answer

i will write that in pretty latex

myininaya · Answer

$$-3(x+9)^2=-63$$

myininaya · Answer

First of all if you write this as something=0 then you are making the problem more hard

anonymous · Answer

yah, that

myininaya · Answer

All you have to do is first divide -3 on both sides like so
$$(x+9)^2=\frac{63}{3}$$

myininaya · Answer

$$(x+9)^2=21$$

myininaya · Answer

now to get rid of the square you need to take square root of both sides

myininaya · Answer

$$\sqrt{(x+9)^2}=\sqrt{21}$$

myininaya · Answer

But this is the same thing as saying 
$$|x+9|=21$$

myininaya · Answer

$$=> x+9=\pm 21$$

myininaya · Answer

Finally subtract 9 on both sides to find x

myininaya · Answer

$$x=\pm 21-9$$

myininaya · Answer

this means you have two solutions
$$x=21-9  \text{ or } x=-21-9$$

anonymous · Answer

in the begining why wouldnt you distribute the -3 ?

anonymous · Answer

i need the problem where i can put it in the quadratic formula

myininaya · Answer

$$-3(x^2+18x+81)=-63$$
divide both sides by -3
$$(x^2+18x+81)=21$$
$$x^2+18x+81=21$$
now subtract 21 on both sides
$$x^2+18x+60=0$$